Method # Split ---------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
Warning
This item was deprecated in version 2019r2. Please use `String.Split` as a replacement.
## Description Creates a one-dimensional array from the `String`. ## Usage **result** = *source*.**Split**(\[*delimiter*\]) | Part | Type | Description | |-------------|----------------------------------------|----------------------------------------------------------------------------------------------------------------------------------------| | *result* | `String` array | Array resulting from breaking *source* into elements using *delimiter* as the field delimiter. | | *source* | `String` | Source string to be parsed into an array. | | *delimiter* | `String` | Optional field delimiter used to parse *Source* into array elements. If *delimiter* is omitted, then a space is used as the delimiter. | ## Notes Use the Split function to create a new `String` array from a list of elements (or fields) that are separated by a delimiter. If the optional parameter, delimiter, is not passed, a single space is assumed as the delimiter. If the delimiter is an empty string, the source string is Split into characters. ## Sample code The section of code specifies the comma delimiter and the second uses the default delimiter. They place each field into an array element, producing a three-element array. The last code section parses the string into individual characters. ``` xojo Var anArray() As String Var s As String s = "Adam,Aardvark,Accountant" anArray = s.Split(",") ' produces 3-element array anArray = s.Split("") ' produces array of individual characters ``` ## Compatibility All project types on all supported operating systems. ## See also `String` parent class; `String` data type; `Var` statement; `Array`, `String.FromArray`, `Arrays` concept